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Thank you for visiting Which of the following is the volume of 0 392 M hydroiodic acid needed to neutralize 100 0 mL of the 0 384 M dimethylamine. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

Which of the following is the volume of 0.392 M hydroiodic acid needed to neutralize 100.0 mL of the 0.384 M dimethylamine solution?

A. 97.7 mL
B. 100.0 mL
C. 102.3 mL
D. 104.6 mL

Answer :

Final answer:

The volume of 0.392 M hydroiodic acid needed to neutralize 100.0 mL of 0.384 M dimethylamine is approximately 97.7 mL, based on the concept of stoichiometry in neutralization reactions.

Explanation:

In a neutralization reaction, the number of moles of an acid should be equal to the number of moles of a base to completely neutralize each other. This is based on the concept of stoichiometry in chemistry. We can use the formula M1V1 = M2V2 where M1 and M2 are the molarities of the solutions and V1 and V2 are their volumes. In this case, M1 is the molarity of dimethylamine (0.384 M), V1 is its volume (100.0 mL), M2 is the molarity of hydroiodic acid (0.392 M), and V2 is what we need to determine.

So, using the M1V1 = M2V2 formula, we calculate: (0.384 M * 100.0 mL) = (0.392 M * V2). Solving for V2 gives us approximately 97.7 mL. Therefore, the volume of hydroiodic acid needed to neutralize the dimethylamine solution is about 97.7 mL, corresponding to option (A).

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