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A hunter aims horizontally at a target on the same level as his rifle. If the bullet leaves his rifle at a velocity of 164 m/s and hits 1.1 meters below the target, how far away is the target?

(Hint: you are looking for [tex]d_x[/tex])

Answer :

Final answer:

The hunter's target is approximately 78 meters away, as calculated using aspects of projectile motion, more specifically using the velocity, time of flight, and gravitational force.

Explanation:

This question is related to physics, specifically, projectile motion.

Projectile motion is a form of motion experienced by an object or particle that is projected near the earth's surface and moves along a curved path under the action of gravity only.

The time of flight is determined only by the vertical motion. In order to find the horizontal distance (dx), we will mainly focus on the vertical displacement of the bullet.

The vertical distance the bullet falls, d = 1.1 m, will be equal to 0.5 * g * (t^2), where g is the acceleration due to gravity, about 9.8 m/s^2.

Solving for time, t, it yields √(2d/g), which is about 0 .475 seconds.

With the horizontal velocity known, we can find the horizontal distance as dx = Vx * t = 164 m/s * 0.475 s = 77.9 m.

Thus, the target is approximately 78 meters away.

Learn more about Projectile Motion here:

https://brainly.com/question/29545516

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