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A rifle is aimed horizontally at a target 52.0 m away. The bullet hits the target 1.50 cm below the aim point. What was the bullet's speed as it left the barrel?

Answer :

The horizontal velocity of the bullet is simply the distance traveled divided by the time of flight is 369 m/s.

The bullet travels 52.0 m horizontally, but drops 1.50 cm in that distance, so we can use the following equation to find the time of flight:

t = sqrt(2h / g)

= [tex]\sqrt{(2 * 0.015 m / 9.81 m/s^2) }[/tex]

= 0.141 s

The horizontal velocity of the bullet is simply the distance traveled divided by the time of flight,

or 52.0 m / 0.141 s = 369 m/s.

Hence, The horizontal velocity of the bullet is simply the distance traveled divided by the time of flight is 369 m/s.

To know more about horizontal velocity here

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