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Calculate the number of moles of each of the ions in the following solution:

38.2 mL of 0.659 M [tex]Al_2(SO_4)_3[/tex]

[tex]Al^{3+}:[/tex] mol

[tex]SO_4^{2-}:[/tex] mol

Answer :

Final answer:

The number of moles of Al3+ in the solution is 0.0504 moles, and the number of moles of SO42- is 0.0756 moles.

Explanation:

To calculate the number of moles of each ion in the solution, we can use the given concentration and volume of the solution. The concentration of the solution is 0.659 M, which means there are 0.659 moles of Al2(SO4)3 in 1 liter of the solution.

First, let's calculate the number of moles of Al2(SO4)3 in the given volume of 38.2 mL:

Number of moles of Al2(SO4)3 = concentration × volume

Number of moles of Al2(SO4)3 = 0.659 M × 0.0382 L

Number of moles of Al2(SO4)3 = 0.0252 moles

Since Al2(SO4)3 contains 2 aluminum ions (Al3+) per formula unit, the number of moles of Al3+ can be calculated as:

Number of moles of Al3+ = 2 × number of moles of Al2(SO4)3

Number of moles of Al3+ = 2 × 0.0252 moles

Number of moles of Al3+ = 0.0504 moles

Similarly, since Al2(SO4)3 contains 3 sulfate ions (SO42-) per formula unit, the number of moles of SO42- can be calculated as:

Number of moles of SO42- = 3 × number of moles of Al2(SO4)3

Number of moles of SO42- = 3 × 0.0252 moles

Number of moles of SO42- = 0.0756 moles

Learn more about calculating moles of ions in a solution here:

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