Answer :

To find the pOH of a solution given the concentration of hydroxide ions [tex]\([OH^-]\)[/tex], we use the formula:

[tex]\[ \text{pOH} = -\log_{10}[OH^-] \][/tex]

Here’s the step-by-step process:

1. Identify the given concentration:
[tex]\[
[OH^-] = 2.0 \times 10^{-2}
\][/tex]

2. Apply the pOH formula:
[tex]\[
\text{pOH} = -\log_{10}(2.0 \times 10^{-2})
\][/tex]

3. Calculate the logarithm:
- Evaluate [tex]\(\log_{10}(2.0 \times 10^{-2})\)[/tex]:
[tex]\[
\log_{10}(2.0 \times 10^{-2}) = \log_{10}(2.0) + \log_{10}(10^{-2})
\][/tex]

- We know that [tex]\(\log_{10}(10^{-2}) = -2\)[/tex], and let's approximate [tex]\(\log_{10}(2.0) \approx 0.301\)[/tex] since [tex]\(\log_{10}(2) \approx 0.301\)[/tex]:
[tex]\[
\log_{10}(2.0 \times 10^{-2}) = 0.301 - 2 = -1.699
\][/tex]

4. Compute the negative logarithm:
[tex]\[
\text{pOH} = -(-1.699) \approx 1.7
\][/tex]

So, the pOH of the solution is approximately [tex]\(1.7\)[/tex].

Therefore, the correct answer is:
[tex]\[ \boxed{1.70} \][/tex]

This matches option A in the list of choices provided:
A. 1.70
B. 3.01
C. 2.00
D. -1.70

Thank you for reading the article What is the pOH of a solution with tex OH 2 0 times 10 2 tex A 1 70 B 3 01 C 2 00. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany

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