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Answer :
To determine the pOH of a solution with an hydroxide ion concentration [tex]\([OH^-]\)[/tex] of [tex]\(2.0 \times 10^{-2}\)[/tex], you can use the formula:
[tex]\[ \text{pOH} = -\log_{10}([OH^-]) \][/tex]
Here's a step-by-step explanation:
1. Identify the Concentration of Hydroxide Ions:
The concentration of [tex]\([OH^-]\)[/tex] given is [tex]\(2.0 \times 10^{-2}\)[/tex].
2. Apply the pOH Formula:
To find the pOH, take the negative logarithm (base 10) of the hydroxide ion concentration.
3. Calculate:
[tex]\[
\text{pOH} = -\log_{10}(2.0 \times 10^{-2})
\][/tex]
When you perform this calculation, the result is approximately:
[tex]\[
\text{pOH} \approx 1.70
\][/tex]
So, the correct answer is:
A. 1.70
[tex]\[ \text{pOH} = -\log_{10}([OH^-]) \][/tex]
Here's a step-by-step explanation:
1. Identify the Concentration of Hydroxide Ions:
The concentration of [tex]\([OH^-]\)[/tex] given is [tex]\(2.0 \times 10^{-2}\)[/tex].
2. Apply the pOH Formula:
To find the pOH, take the negative logarithm (base 10) of the hydroxide ion concentration.
3. Calculate:
[tex]\[
\text{pOH} = -\log_{10}(2.0 \times 10^{-2})
\][/tex]
When you perform this calculation, the result is approximately:
[tex]\[
\text{pOH} \approx 1.70
\][/tex]
So, the correct answer is:
A. 1.70
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