Thank you for visiting A rifle is aimed horizontally at a target 50 m away The bullet hits 1 25 m below the target a What was the bullet. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
To find the flight time of the bullet, we use the formulas for vertical motion and solve for time. The flight time is approximately 0.32 seconds. To find the speed of the bullet as it left the barrel, we use the horizontal motion equation and divide the distance traveled by the flight time. The speed is approximately 156.25 m/s.
Explanation:
Physics
To solve this problem, we can use the horizontal motion equations and the vertical motion equations. Let's start with part (a) of the question:
(a) The bullet is aimed horizontally, so its initial vertical velocity is 0 m/s. The time it takes for the bullet to hit the target can be found using the formula:
Δy = v0y * t + (1/2) * a * t2
Since the bullet is hitting 1.25 m below the target, we can set Δy = -1.25 m and solve for t. The acceleration in the vertical direction is the acceleration due to gravity, which is -9.8 m/s2. Rearranging the equation, we get:
t = √(2 * (Δy - (1/2) * a * t2)) / a
Plugging in the values, we have:
t = √(2 * (-1.25 m - (1/2) * (-9.8 m/s2) * t2)) / (-9.8 m/s2)
Simplifying the equation and solving for t, we find that the flight time of the bullet is approximately 0.32 seconds.
(b) Speed as it left the barrel
To find the speed of the bullet as it left the barrel, we can use the horizontal motion equation:
Δx = v0x * t
The horizontal velocity of the bullet remains constant throughout its flight, so we have:
v0x = Δx / t
Plugging in the values, we have:
v0x = (50 m) / (0.32 s)
Simplifying the equation, we find that the speed of the bullet as it left the barrel is approximately 156.25 m/s.
Learn more about flight time and speed of a bullet here:
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