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Answer :
Final answer:
To warm 1.70 kg of sand from 28.0 °C to 100.0 °C, the amount of heat energy required is approximately 101,976 joules, calculated using the specific heat capacity of sand and the temperature change.
Explanation:
The student is asking about the amount of heat transfer required to warm a certain mass of sand from one temperature to another. To calculate this, we use the formula:
Q = mcΔT
where:
Plugging in the values given:
Q = (1.70 kg)(830 J/kg°C)(100.0 °C - 28.0 °C)
Q = 1.70 kg × 830 J/kg°C × 72.0 °C
Q = 101,976 J
Therefore, the amount of heat energy required to warm 1.70 kg of sand from 28.0 °C to 100.0 °C is approximately 101,976 joules.
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