Thank you for visiting A 1 70 meter long pole is balanced vertically on its tip It starts to fall and its lower end does not slip Part A. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
The speed of the upper end of the pole just before it hits the ground will be approximately 7.64 m/s.
The initial potential energy of the pole is given by:
PE_initial = m * g * L
At the moment just before it hits the ground, the potential energy is completely converted into kinetic energy:
KE_final = 1/2 * m * v²
According to the conservation of energy principle, the initial potential energy is equal to the final kinetic energy:
PE_initial = KE_final
m * g * L = 1/2 * m * v²
Simplifying the equation:
g * L = 1/2 * v²
To find the speed v, we can solve for it:
v² = 2 * g * L
v = √(2 * g * L)
Now we can substitute the given values:
v = √(2 * 9.8 m/s² * 1.70 m)
Calculating the result:
v ≈ 7.64 m/s
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