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Gravity is [tex]0.930 \, \text{m/s}^2[/tex]. The radius of the Moon is [tex]1.70 \times 10^6 \, \text{m}[/tex].

(a) Determine the astronaut's orbital speed in meters per second (m/s).

(b) Determine the period of the orbit.

Answer :

Final answer:

The astronaut's orbital speed is approximately 1518 m/s, and the period of the orbit is approximately 7066 seconds.

Explanation:

To calculate the astronaut's orbital speed, we can use the equation v = √(g * r), where g is the acceleration due to gravity and r is the radius of the Moon. Substituting the given values, we get v = √(0.930 m/s2 * 1.70x106 m) = 1518 m/s.

To determine the period of the orbit, we can use the equation T = 2πr / v, where T is the period and v is the orbital speed. Substituting the known values, we get T = 2π * 1.70x106 m / 1518 m/s = 7066 seconds.

Learn more about Orbital speed and period here:

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