Thank you for visiting A scientist removed a sample of 39 1 g of a chemical from a container The sample was 5 frac 3 4 g less than. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
To find the total mass of nicotine before a 39.1 g sample was removed, we solve the equation 3x - 5.75 = 39.1, which gives us the total mass as 14.95 g.
The student has provided information about the mass of a chemical sample that was taken from a container and its relationship to the total mass of nicotine. To determine the total mass of the chemical nicotine before the 39.1 g sample was removed, we set up the following equation based on the given data: Let x be the total mass of nicotine in the container. According to the problem, a sample that is 5 3/4 g less than three times the total mass was removed, leading to the equation 3x - 5.75 = 39.1. Solving this equation for x gives us the total mass of the nicotine before the sample was removed.
To solve for x, we add 5.75 to both sides of the equation to get 3x = 44.85 and then divide both sides by 3, resulting in x = 14.95 g. Therefore, the total mass of the nicotine in the container before the sample was removed was 14.95 g.
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