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[tex]1.70 \times 10^{13}[/tex] electrons flow through a transistor in [tex]3.40 \text{ ms}[/tex]. What is the current through the transistor?

Answer :

The current through the transistor when 1.70 x 10¹³ electrons flow through it in 3.40 ms is 0.80 x 10⁻³ A or 0.80 mA.

To find the current through the transistor when 1.70 x 10¹³ electrons flow through it in 3.40 ms, follow these steps:


1. Determine the total charge of the electrons:
Charge of one electron = 1.60 x 10⁻¹â¹ C (coulombs)
Total charge = (1.70 x 10¹³ electrons) x (1.60 x 10⁻¹â¹ C/electron) = 2.72 x 10⁻⁶ C

2. Convert the time from ms to seconds:
3.40 ms = 3.40 x 10⁻³ s (seconds)

3. Calculate the current:
Current (I) = Total charge (Q) / Time (t)
I = (2.72 x 10⁻⁶ C) / (3.40 x 10⁻³ s) = 0.80 x 10⁻³ A (amperes)

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