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Answer :
For question (1) The hydroxide ion concentration in the solution is 0.041148 M, and for question(2) the concentration of Ca(OH)â‚‚ is 0.020574 M.
To determine the concentration of the hydroxide ion and Ca(OH)â‚‚ from the given data in question(1), we need to follow these steps:
First, identify the balanced chemical equation for the reaction:
Ca(OH)â‚‚(aq) + 2HCl(aq) → CaClâ‚‚(aq) + 2Hâ‚‚O(l)
Calculate the moles of HCl used in the titration:
Moles of HCl = Molarity of HCl × Volume of HCl in Liters = 0.027 M × 38.1 mL / 1000 = 0.0010287 moles HCl
Using the stoichiometry of the reaction, determine the moles of Ca(OH)â‚‚:
Since 2 moles of HCl react with 1 mole of Ca(OH)â‚‚:
Moles of Ca(OH)â‚‚ = moles of HCl / 2 = 0.0010287 / 2 = 0.00051435 moles Ca(OH)â‚‚
Calculate the concentration of Ca(OH)â‚‚ in the original solution:
Concentration of Ca(OH)â‚‚ = moles of Ca(OH)â‚‚ / volume of Ca(OH)â‚‚ solution in Liters = 0.00051435 moles / (25.0 mL / 1000) = 0.020574 M
Similarly, in question (2)calculate the hydroxide ion concentration:
Since each mole of Ca(OH)â‚‚ produces 2 moles of OHâ»:
Hydroxide ion concentration [OHâ»] = 2 × 0.020574 M = 0.041148 M
Therefore, the hydroxide ion concentration is 0.041148 M and the concentration of Ca(OH)â‚‚ is 0.020574 M.
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