Thank you for visiting How many grams of Na 3 PO 4 are there in a 35 9 mL solution of Na 3 PO 4 if the density of. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The mass of Na3PO4 in a 35.9 mL solution is found by multiplying the density by the volume. The solution thus contains approximately 39.49 grams of Na3PO4.
Therefore correct option is 1.
Explanation:
The subject of this question is Chemistry and it's a problem related to molarity and density. To solve this problem, we need to multiply the volume of the solution by its density to find the mass. The formula is mass = density * volume. So, 1.10g/mL * 35.9mL = 39.49g. Therefore, there are approximately 39.49 grams of Na3PO4 in a 35.9 mL solution of Na3PO4.
Learn more about Molarity here:
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