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Thank you for visiting A rifle can shoot a 4 2 g bullet at 965 m s If the rifle weighs 5 kg what is the force it exerts. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

A rifle can shoot a 4.2 g bullet at 965 m/s. If the rifle weighs 5 kg, what is the force it exerts on your shoulder if it recoils for 10 ms?

Answer :

The force exerted on your shoulder by the rifle is 8.19 N.

To find the force exerted on your shoulder, first, we need to calculate the momentum of the bullet and the rifle using the equation p = mv. The bullet has a mass of 0.0042 kg and a velocity of 965 m/s, so its momentum is 0.0042 kg * 965 m/s = 4.053 kg*m/s.

According to the law of conservation of momentum, the total momentum before and after firing must be equal. Thus, the rifle's momentum is equal to -4.053 kg*m/s. Next, we'll find the rifle's recoil velocity using the equation p = mv. The rifle has a mass of 5 kg, so its recoil velocity is -4.053 kg*m/s / 5 kg = -0.8106 m/s.

Finally, we can find the force exerted on your shoulder using the equation F = Δp/Δt, where Δp is the change in momentum and Δt is the time interval (10 ms, or 0.01 s).

The force is (-4.053 kg*m/s - 0 kg*m/s) / 0.01 s = -4.053 kg*m/s / 0.01 s = -405.3 N. However, the force exerted on your shoulder is opposite to the force exerted on the rifle, so the force on your shoulder is 405.3 N.

To know more about law of conservation of momentum click on below link:

https://brainly.com/question/17140635#

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