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Calculate the rifle recoil velocity of a 6.0 kg rifle that shoots a 0.040 kg bullet at a speed of 420 m/s.

Answer :

From the principle of the conservation of momentum, the recoil velocity is 2.8 m/s.

What is the recoil velocity?

Here the principle of the conservation of the linear momentum just comes to our mind. We know that the total momentum before collsion must be equal to the total momentum after the Collison and that is what we need to apply to solve the question that we have here.

From the foregoing;

Total momentum before Collison = Total momentum after Collison

(6.0 kg * 0 m/s) + (0.040- kg * 420 m/s) = (6.0 kg * v) + (0.040- kg * 0 m/s)

v = (0.040- kg * 420 m/s) /6.0 kg

v = 2.8 m/s

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Rewritten by : Jeany

The recoil velocity of a 6.0 kg rifle that shoots a 0.040-kg bullet at 420 m/s is 2.8 m/s, calculated using the conservation of momentum principle.

When a rifle fires a bullet, the conservation of momentum dictates that the rifle will experience a recoil with a velocity opposite to the bullet's direction. According to the law of conservation of momentum, the total momentum before and after firing must be the same. Thus, if a rifle shoots a bullet, the product of the mass of the bullet and its velocity will be equal to the product of the mass of the rifle and its recoil velocity, but in the opposite direction.

Recoil velocity V(rifle) of the rifle can be calculated using the formula:

m(bullet) × v(bullet) = m(rifle) × V(rifle)

Plugging in the given values:

0.040 kg × 420 m/s = 6.0 kg × V(rifle)

Therefore:

V(rifle) = (0.040 kg × 420 m/s) / 6.0 kg

V(rifle) = 2.8 m/s

The recoil velocity of the rifle is 2.8 m/s.