Thank you for visiting A cheetah reaches a final velocity of 39 4 ft sec in 1 25 seconds If it accelerated at a rate of 2 10 ft. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The cheetah's initial velocity was 36.9 ft/sec, and it traveled approximately 61.5 ft in 1.25 seconds.
Explanation:
To find the cheetah's initial velocity, we can use the formula:
v = u + at
Where:
v is the final velocity (39.4 ft/sec)u is the initial velocity (unknown)a is the acceleration (2.10 ft/sec²)t is the time taken (1.25 seconds)Substituting the given values into the formula, we get:
39.4 = u + 2.10 × 1.25
Solving for u, we find:
u = 36.9 ft/sec
To find the distance traveled by the cheetah, we can use the formula:
s = ut + 0.5at²
Substituting the given values into the formula, we get:
s = 36.9 × 1.25 + 0.5 × 2.10 × (1.25)²
s ≈ 61.5 ft
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