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Answer :
The instantaneous voltage of the sine wave for the given phase angles are:
- a. 25.98 mV
- b. 76.60 mV
- c. 100 mV
- d. -64.28 mV
- e. 0 mV
- f. 64.28 mV
- g. -76.60 mV
How to solve for the instantaneous voltage
a. θ = 15 degrees
V = 100 mV * sin(15°) = 25.98 mV
b. θ = 50 degrees
V = 100 mV * sin(50°) = 76.60 mV
c. θ = 90 degrees
V = 100 mV * sin(90°) = 100 mV
d. θ = 150 degrees
V = 100 mV * sin(150°) = -64.28 mV
e. θ = 180 degrees
V = 100 mV * sin(180°) = 0 mV
f. θ = 240 degrees
V = 100 mV * sin(240°) = 64.28 mV
g. θ = 330 degrees
V = 100 mV * sin(330°) = -76.60 mV
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