High School

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Can anyone find \(\bar{d}\) (the d with the line over it) and explain it to me?

For this problem, five trials are conducted at 8 AM and then at 12 AM.

The 8 AM trials are: 98.4, 98.6, 97.8, 97.1, and 97.5.

The 12 AM trials are: 98.9, 99.0, 97.9, 96.6, and 97.7.

The correct answer is \(-0.14\), but I can't get that answer.

Answer :

Answer:

d-bar= ∑d/n= -0.7/ 5= -0.14

Step-by-step explanation:

Eight am 12 am difference (8:00am- 12:00 am)= d

98.4 98.9 (98.4-98.9=) -0.5

98.6 99 (98.6-99=) -0.4

97.8 97.9 (97.8-97.9=) - 0.1

97.1 96.6 (97.1-96.6=)+0.5

97.5 97.7 (97.5-97.7=)-0.2

∑ -0.7

d= difference between 8 am and 12 am

First we subtract the 12.00 am times from 8:00 am times.

Then we add all the differences to get the total difference ∑d.

∑d= -0.7= total of the difference between two times.

n= number of observations=5

Putting the values in the formula would give the answer.

d-bar= d`= ∑d/n= -0.7/ 5= -0.14

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Rewritten by : Jeany