College

Thank you for visiting Look at the picture Options A PQ 9 27 Area 38 2B PQ 9 267 Area 58 2C PQ 8 27 Area 28 2D PQ. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

Look at the picture.

Options:

A. PQ = 9.27, Area = 38.2
B. PQ = 9.267, Area = 58.2
C. PQ = 8.27, Area = 28.2
D. PQ = 7.23, Area = 42.2​

Look at the picture Options A PQ 9 27 Area 38 2B PQ 9 267 Area 58 2C PQ 8 27 Area 28 2D PQ

Answer :

Answer:

c

Step-by-step explanation:

I think it's c I might be wrong though not sure

Thank you for reading the article Look at the picture Options A PQ 9 27 Area 38 2B PQ 9 267 Area 58 2C PQ 8 27 Area 28 2D PQ. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany

Answer:

C

Step-by-step explanation:

(i)

given a triangle with 2 sides and the included angle known

to find the third side use the Cosine rule

a² = b² + c² - 2bc cosA

adapting the formula to describe Δ PQR

r² = p² + q² - 2pq cosR

here r = PQ, p = QR = 7.6 , q = PR = 8.4 and ∠ R = 62° , then

r² = 7.6² + 8.4² - (2 × 7.6 × 8.4 × cos62° )

= 57.76 + 70.56 - 59.942

= 128.32 - 59.942

= 68.376 ( take square root of both sides )

r = [tex]\sqrt{68.378}[/tex]

≈ 8.27

that is PQ ≈ 8.27 cm ( to 2 decimal places )

(11)

the area (A) is then calculated as

A = [tex]\frac{1}{2}[/tex] pq sinR

= 0.5 × 7.6 × 8.4 × sin62°

≈ 28.2

that is area of Δ PQR ≈ 28.2 cm² ( to 1 decimal place )