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A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of [tex]\frac{2\pi}{3}[/tex].

A. 6.67 inches
B. 10.47 inches
C. 20.94 inches
D. 62.8 inches

Answer :

The approximate length of the arc intersected by the central angle is [tex]20.94[/tex] inches.

To find the approximate length of the arc of a circle that corresponds to a central angle of [tex]\frac{2\pi}{3}[/tex] radians with a radius of 10 inches, we can use the arc length formula:

[tex]L = r\theta[/tex]

Where:

  • [tex]L[/tex] = arc length
  • [tex]r[/tex] = radius of the circle
  • [tex]\theta[/tex] = central angle in radians

In this case:

  • The radius [tex]r = 10[/tex] inches
  • The central angle [tex]\theta = \frac{2\pi}{3}[/tex] radians

Now, substitute the values into the formula:

[tex]L = 10 \times \frac{2\pi}{3}[/tex]

Calculating this gives:

[tex]L = \frac{20\pi}{3} = \frac{20 \times 3.14159}{3} = \frac{62.8318}{3} = 20.94 \text{ inches}[/tex]

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Rewritten by : Jeany