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How many moles of methane are produced when 36.6 moles of carbon dioxide gas react with excess hydrogen gas?

Answer :

Final answer:

In a theoretical or indirect conversion process not detailed in the examples, where carbon dioxide reacts with hydrogen to produce methane, 36.6 moles of carbon dioxide would produce 36.6 moles of methane, assuming a simple 1:1 stoichiometry for COâ‚‚ to CHâ‚„.

Explanation:

The question pertains to the reaction of carbon dioxide gas with hydrogen gas to produce methane. According to the information provided, one mole of methane molecules reacts with two moles of oxygen molecules to yield one mole of carbon dioxide molecules and two moles of water molecules. However, the direct reaction converting carbon dioxide to methane in the presence of hydrogen is not directly provided in the examples.

Given the stoichiometry mentioned, a direct conversion from carbon dioxide to methane isn't specified. Instead, the given reactions suggest the combustion of methane or its reaction with water, leading to the formation of carbon dioxide rather than its conversion back to methane.

Given this, it's assumed that the question implies a theoretical reverse process or a different reaction pathway (such as a methanation process that is not detailed in the examples given), which could convert carbon dioxide back to methane using hydrogen.

Typically, in a methanation reaction, carbon dioxide (COâ‚‚) reacts with hydrogen (Hâ‚‚) to produce methane (CHâ‚„) and water. If we assume a simple stoichiometry of 1:1 for COâ‚‚ to CHâ‚„ in a direct or catalyzed process, then 36.6 moles of carbon dioxide would theoretically produce 36.6 moles of methane under conditions allowing for complete conversion.

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Rewritten by : Jeany

Answer:

[tex]36.6molCH_4[/tex]

Explanation:

Hello,

The carried out chemical reaction is:

[tex]CO_2+4H_2-->CH_4+2H_2O[/tex]

With the given moles of carbon dioxide, one computes the required moles of methane by applying the following stoichiometric relationship based on the undergoing chemical reaction.

[tex]36.6molesCO_2*\frac{1molCH_4}{1molCO_2}=36.6molCH_4[/tex]

Best regards