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Answer :
Final answer:
To find the mass of H2O produced, we need to determine the limiting reagent first. The equation tells us that the stoichiometric ratio of O2 to H2O is 4:2, which simplifies to 2:1. We can use that ratio to convert the mass of O2 given (35.0 g) to the mass of H2O produced. Therefore, the mass of H2O produced is 9.85 g.
Explanation:
To find the mass of H2O produced, we need to determine the limiting reagent first. The equation tells us that the stoichiometric ratio of O2 to H2O is 4:2, which simplifies to 2:1. We can use that ratio to convert the mass of O2 given (35.0 g) to the mass of H2O produced.
Step-by-step:
- Calculate the molar mass of O2: 32.0 g/mol
- Calculate the moles of O2: 35.0 g / 32.0 g/mol = 1.094 mol
- Use the stoichiometric ratio to convert moles of O2 to moles of H2O: 1.094 mol O2 * (2 mol H2O / 4 mol O2) = 0.547 mol H2O
- Calculate the molar mass of H2O: 18.02 g/mol
- Calculate the mass of H2O produced: 0.547 mol H2O * 18.02 g/mol = 9.85 g
Therefore, the mass of H2O produced is 9.85 g. So, the correct answer is b) 9.85 g.
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