High School

Thank you for visiting Calculate the electronegativity of fluorine from the following data Bond energy of H H bond E H H 104 2 text kcal mol 1 Bond. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

Calculate the electronegativity of fluorine from the following data:

- Bond energy of H-H bond: \( E_{H-H} = 104.2 \, \text{kcal mol}^{-1} \)
- Bond energy of F-F bond: \( E_{F-F} = 36.6 \, \text{kcal mol}^{-1} \)
- Bond energy of H-F bond: \( E_{H-F} = 134.6 \, \text{kcal mol}^{-1} \)
- Electronegativity of Hydrogen (\( X_H \)) = 2.1

Choose the correct electronegativity of fluorine:

A. 3.87
B. 2.76
C. -3.87
D. -2.76

Answer :

The electronegativity of fluorine is 3.87. Option A is the correct answer.

To calculate the electronegativity of fluorine, we can use the concept of bond energies and the Pauling scale.

Given:

- Bond energy of H-H bond (Eâ‚•â‚‹â‚•) = 104.2 kcal/mol

- Bond energy of F-F bond (Eâ‚‹) = 36.6 kcal/mol

- Bond energy of H-F bond (Eâ‚•â‚‹) = 134.6 kcal/mol

- Electronegativity of hydrogen (Xâ‚•) = 2.1

1. Calculate the electronegativity of fluorine (Xâ‚‹) using the bond energies:

Xâ‚‹ - Xâ‚• = √(Eâ‚•â‚‹ - Eâ‚•â‚‹â‚•) - √(Eâ‚‹ - Eâ‚•â‚‹â‚•)

Xâ‚‹ - 2.1 = √(134.6 - 104.2) - √(36.6 - 104.2)

Xâ‚‹ - 2.1 = √30.4 - √(-67.6)

Xâ‚‹ - 2.1 = 5.51 - 8.22

Xâ‚‹ - 2.1 = -2.71

Xâ‚‹ = -2.71 + 2.1

Xâ‚‹ = 3.87

Therefore, the electronegativity of fluorine is 3.87.

The correct answer is option A.

Thank you for reading the article Calculate the electronegativity of fluorine from the following data Bond energy of H H bond E H H 104 2 text kcal mol 1 Bond. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany

Other Questions