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Answer :
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The median of a data set is the middle value when the data set is ordered. If the data set has an odd number of values, it’s the middle value. If the data set has an even number of values, it is the average of the two middle values.
Now, consider the data set has median [tex]\( h \)[/tex].
If we subtract 625 from each value in the data set, the new data set values will be:
[tex]\[ x_1 - 625, \; x_2 - 625, \; \ldots, \; x_n - 625 \][/tex]
Notice that subtracting the same constant from each data point shifts all the values by the same amount. However, the order of the values and their relative positions remain the same. Thus, the new median will simply be the old median minus 625.
So, if the original median was [tex]\( h \)[/tex], the new median of the resulting data set will be:
[tex]\[ h - 625 \][/tex]
Therefore, the correct answer is:
D. [tex]\( h - 625 \)[/tex]
The median of a data set is the middle value when the data set is ordered. If the data set has an odd number of values, it’s the middle value. If the data set has an even number of values, it is the average of the two middle values.
Now, consider the data set has median [tex]\( h \)[/tex].
If we subtract 625 from each value in the data set, the new data set values will be:
[tex]\[ x_1 - 625, \; x_2 - 625, \; \ldots, \; x_n - 625 \][/tex]
Notice that subtracting the same constant from each data point shifts all the values by the same amount. However, the order of the values and their relative positions remain the same. Thus, the new median will simply be the old median minus 625.
So, if the original median was [tex]\( h \)[/tex], the new median of the resulting data set will be:
[tex]\[ h - 625 \][/tex]
Therefore, the correct answer is:
D. [tex]\( h - 625 \)[/tex]
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