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A projectile is launched at an angle of 29 degrees above the horizontal with an initial velocity of 36.6 m/s at an unknown height.

The magnitude of the vertical velocity upon returning to its original, unknown height is _____ m/s.

Answer :

The magnitude of the unknown height of the projectile is determined as 16.1 m.

Magnitude of the height

The magnitude of the height of the projectile is calculated as follows;

H = u²sin²θ/2g

H = (36.6² x (sin 29)²)/(2 x 9.8)

H = 16.1 m

Thus, the magnitude of the unknown height of the projectile is determined as 16.1 m.

Learn more about height here: https://brainly.com/question/1739912

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