Thank you for visiting An ore contains Fe 3 O 4 and no other iron The iron in a 36 6 gram sample of the ore is all converted. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
To solve this problem, let us first find for the molar
mass of Fe2O3 and Fe3O4.
Fe = 55.85 g/mol and O = 16 g/mol
Therefore,
Fe2O3 = 159.7 g/mol
Fe3O4 = 231.55 g/mol
We are given that there are 29 g of Fe2O3, we calculate
for the amount of Fe from this in moles:
mol Fe = 29 g Fe2O3 (1 / 159.7 g/mol) (2 mol Fe / 1 mol
Fe2O3)
mol Fe = 0.363 mol
Converting this to Fe3O4:
mass Fe3O4 = 0.363 mol Fe (1 mol Fe3O4 / 3 mol Fe) (231.55
g/mol)
mass Fe3O4 = 28.03 g
Therefore there are 28.03g of Fe3O4 in the ore.
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Rewritten by : Jeany
