Thank you for visiting A physics book sides off a horizontal tabletop with Part A a speed of 1 70 m s It strikes the floor in 0 350. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Part A
To find the height of the tabletop above the floor, we can use the equation of motion: h = (1/2) * g * t^2
Where: - h is the height of the tabletop above the floor - g is the acceleration due to gravity (approximately 9.8 m/s^2) - t is the time taken for the book to reach the floor (0.350 s in this case)
Plugging in the values, we get: h = (1/2) * 9.8 * (0.350)^2 = 0.6 m
Therefore, the height of the tabletop above the floor is 0.6 meters.
Part B
To find the horizontal distance from the edge of the table to the point where the book strikes the floor, we can use the equation of motion:
d = v * t
Where: - d is the horizontal distance - v is the horizontal component of the book's velocity just before it reaches the floor - t is the time taken for the book to reach the floor (0.350 s in this case)
Part C
However, we need the horizontal component of the book's velocity to proceed.
Unfortunately, the question does not provide sufficient information to calculate this value.
Please double-check the question or provide any additional information that may be needed.
Part D
To find the vertical component of the book's velocity just before it reaches the floor, we can use the equation of motion:
v = g * t
Where: - v is the vertical component of the book's velocity - g is the acceleration due to gravity (approximately 9.8 m/s^2) - t is the time taken for the book to reach the floor (0.350 s in this case)
Plugging in the values, we get: v = 9.8 * 0.350 = 3.43 m/s
Therefore, the vertical component of the book's velocity just before it reaches the floor is 3.43 meters per second.
To know more about gravity, visit:
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Rewritten by : Jeany
