What is the boiling point of water at an elevation of [tex]1.70 \times 10^4[/tex] feet?

Question

10-05-2025
Chemistry

High School

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What is the boiling point of water at an elevation of [tex]1.70 \times 10^4[/tex] feet?

Answer :

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damonsalvator7878 damonsalvator7878 · Answer 1 · 2025-01-23T14:46:14-05:00

Final answer:

The boiling point of water at an elevation of 1.70 × 10^4 meters is approximately 85.6°C.

Explanation:

To determine the boiling point of water at a given elevation, we can use the fact that the boiling point of water decreases as elevation increases due to the decrease in atmospheric pressure. The relationship between boiling point and elevation can be approximated using the formula:

T_b = T_{b0} - 0.0065 × h

Where T_b is the boiling point at the given elevation, T_{b0} is the standard boiling point of water (100°C at sea level), and h is the elevation in meters.

Substituting the given elevation of 1.70 × 10^4 meters into the formula:

T_b = 100°C - 0.0065 × (1.70 × 10^4)

T_b = 100°C - 110.5°C

T_b ≈ 85.6°C

Thus, the boiling point of water at an elevation of 1.70 × 10^4 meters is approximately 85.6°C.

In summary, as elevation increases, atmospheric pressure decreases, leading to a decrease in the boiling point of water. By applying the elevation to the formula relating boiling point and elevation, we find that at an elevation of 1.70 × 10^4 meters, the boiling point of water decreases to approximately 85.6°C, as compared to its standard boiling point of 100°C at sea level.