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Which polynomial can be factored using the binomial theorem?

A. [tex]25x^2 + 75x + 225[/tex]

B. [tex]25x^2 + 300x + 225[/tex]

C. [tex]625x^4 + 1,875x^3 + 5,625x^2 + 16,875x + 50,625[/tex]

D. [tex]625x^4 + 7,500x^3 + 33,750x^2 + 67,500x + 50,625[/tex]

Answer :

To find which polynomial factors as a perfect power (that is, it can be written as a constant multiplied by a binomial raised to an integer power), we can factor each option individually.

1. For the polynomial
[tex]$$25x^2 + 75x + 225,$$[/tex]
factoring gives
[tex]$$25(x^2 + 3x + 9).$$[/tex]
The quadratic factor does not have the form [tex]$(x + b)^n$[/tex], so it does not represent a perfect power derived from the Binomial Theorem.

2. For the polynomial
[tex]$$25x^2 + 300x + 225,$$[/tex]
factoring gives
[tex]$$25(x^2 + 12x + 9).$$[/tex]
Again, the quadratic is not a perfect square of a binomial.

3. For the polynomial
[tex]$$625x^4 + 1875x^3 + 5625x^2 + 16875x + 50625,$$[/tex]
factoring gives
[tex]$$625(x^4 + 3x^3 + 9x^2 + 27x + 81).$$[/tex]
The quartic inside does not factor as a single binomial raised to a power.

4. For the polynomial
[tex]$$625x^4 + 7500x^3 + 33750x^2 + 67500x + 50625,$$[/tex]
factoring gives
[tex]$$625(x+3)^4.$$[/tex]
Here, the expression is exactly in the form [tex]$$a\,(x+b)^n,$$[/tex] with [tex]$a=625$[/tex], [tex]$b=3$[/tex], and [tex]$n=4$[/tex]. This is the binomial expansion of [tex]$(x+3)^4$[/tex] multiplied by 625.

Since the only option that factors into a constant times a perfect power (a binomial raised to a power) is option 4, it can be factored using the Binomial Theorem.

Thus, the answer is option 4.

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