Thank you for visiting If your front lawn is 24 0 feet wide and 20 0 feet long and each square foot of lawn accumulates 1050 new snowflakes every. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
First find the area of the front lawn:
Area = length * width
Area = 24.0ft * 20.0ft
Area = 480ft^2
Next, find the weight in kilograms of the snow per square foot per hour per ft^2:
[tex]weight\ per\ ft^{2}=\frac{1050\ snowflakes}{minute}\\\\weight\ per\ ft^{2}=\frac{1050\ snowflakes}{minute}*\frac{1.70\ milligrams}{snowflake}*\frac{1\gram}{1000\milligrams}*\frac{1\kilogram}{1000\grams}* \frac{60\minutes}{1\hour}\\\\weight\ per\ ft^{2}=\frac{1050*1.70}{1000*1000*60}*\frac{kg}{hour}=2.975*10^{-5}\ \frac{kg}{hour}\\\\weight=2.975*10^{-5}\ \frac{kg}{hour*ft^{2}}[/tex]
Now multiply the area of the lawn by the weight of the snow per hour per ft^2:
[tex]weight\ of\ snow=lawn\ area*weight\ per\ hour\ per ft^{2}\\\\weight=480\ ft^{2}*2.975*10^{-5}\ \frac{kg}{hour*ft^{2}}\\\\weight=0.01428\ \frac{kg}{hour}[/tex]
Thus your answer is .01428 kg.
Area = length * width
Area = 24.0ft * 20.0ft
Area = 480ft^2
Next, find the weight in kilograms of the snow per square foot per hour per ft^2:
[tex]weight\ per\ ft^{2}=\frac{1050\ snowflakes}{minute}\\\\weight\ per\ ft^{2}=\frac{1050\ snowflakes}{minute}*\frac{1.70\ milligrams}{snowflake}*\frac{1\gram}{1000\milligrams}*\frac{1\kilogram}{1000\grams}* \frac{60\minutes}{1\hour}\\\\weight\ per\ ft^{2}=\frac{1050*1.70}{1000*1000*60}*\frac{kg}{hour}=2.975*10^{-5}\ \frac{kg}{hour}\\\\weight=2.975*10^{-5}\ \frac{kg}{hour*ft^{2}}[/tex]
Now multiply the area of the lawn by the weight of the snow per hour per ft^2:
[tex]weight\ of\ snow=lawn\ area*weight\ per\ hour\ per ft^{2}\\\\weight=480\ ft^{2}*2.975*10^{-5}\ \frac{kg}{hour*ft^{2}}\\\\weight=0.01428\ \frac{kg}{hour}[/tex]
Thus your answer is .01428 kg.
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