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Completely factor [tex]f(x) = 256x^4 - 625[/tex].

Answer :

To factor the polynomial [tex]\( f(x) = 256x^4 - 625 \)[/tex], we first recognize that it is a difference of squares. The expression can be rewritten as:

[tex]\[ f(x) = (16x^2)^2 - 25^2 \][/tex]

This is a difference of squares and can be factored using the formula [tex]\( a^2 - b^2 = (a - b)(a + b) \)[/tex]. Here, [tex]\( a = 16x^2 \)[/tex] and [tex]\( b = 25 \)[/tex]. Applying the formula gives:

[tex]\[ f(x) = (16x^2 - 25)(16x^2 + 25) \][/tex]

The first term, [tex]\( 16x^2 - 25 \)[/tex], can also be further factored since it itself is a difference of squares:

[tex]\[ 16x^2 - 25 = (4x)^2 - 5^2 = (4x - 5)(4x + 5) \][/tex]

So, the completely factored form of the original polynomial is:

[tex]\[ f(x) = (4x - 5)(4x + 5)(16x^2 + 25) \][/tex]

Thus, the polynomial [tex]\( f(x) = 256x^4 - 625 \)[/tex] factors into [tex]\((4x - 5)(4x + 5)(16x^2 + 25)\)[/tex].

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