Thank you for visiting The specific rotation of a pure S enantiomer is 61 0 degrees What percentage of a mixture of the two enantiomeric forms is the S. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The percentage of the (S) form in the mixture is 60.0%.
Explanation:
The specific rotation of a pure (S) enantiomer is +61.0 degrees. To find the percentage of the (S) form in a mixture, we can use the formula: Percentage of (S) form = (Specific Rotation of the Mixture - Specific Rotation of the (R) form) / (Specific Rotation of the (S) form - Specific Rotation of the (R) form) x 100
To find the percentage of the (S) enantiomer in the mixture, you can use the formula: % (S) enantiomer = (Observed rotation / Specific rotation of (S)) * 100.
% (S) enantiomer = (+36.6 / +61.0) * 100 = 60%.
So, the (S) enantiomer makes up 60% of the mixture, while the (R) enantiomer constitutes the remaining 40%.
Plugging in the values given, we get: Percentage of (S) form = (+36.6 - 0) / (+61.0 - 0) x 100 = 60.0%
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