High School

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A student on the balcony of his apartment building (height of 10 m) launches a tennis ball straight up at a velocity of 29.4 m/s. What is the ball's speed when it reaches the sidewalk below?

A. 19.4 m/s
B. 29.4 m/s
C. 9.8 m/s
D. 39.4 m/s

Answer :

Final answer:

The speed of the tennis ball when it reaches the sidewalk below will be 34.3 m/s, matching option D.

Explanation:

This is a high school physics problem dealing with the concepts of free fall and kinematics. When the student on the balcony launches the ball straight up at a velocity of 29.4 m/s, the ball will eventually reach peak height then fall back down due to gravity. Presuming the absence of air resistance, we apply the equation for final velocity v_f = sqrt(v_i^2 + 2*a*d), where v_i is the initial velocity, a is acceleration (equal to gravity when the object is in free fall), and d is the distance. Plugging in the given values (v_i = 29.4 m/s, a = -9.81 m/s², d = -10 m), the final speed whereby negative indicates direction not magnitude would be 34.3 m/s taking the absolute would yield 34.3m/s, matching option D.

Learn more about Free Fall Kinematics here:

https://brainly.com/question/29207036

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