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Answer :
To calculate the pOH of a solution with a hydroxide ion concentration [tex]\([\text{OH}^-]\)[/tex] of [tex]\(2.0 \times 10^{-2}\)[/tex], you can use the formula:
[tex]\[ \text{pOH} = -\log_{10}[\text{OH}^-] \][/tex]
Here are the steps to solve this:
1. Identify the Hydroxide Ion Concentration:
The concentration of hydroxide ions in the solution is [tex]\(2.0 \times 10^{-2}\)[/tex].
2. Calculate the pOH:
Use the formula [tex]\(\text{pOH} = -\log_{10}[2.0 \times 10^{-2}]\)[/tex].
3. Use a Calculator or Logarithm Table:
Evaluate [tex]\(-\log_{10}(2.0 \times 10^{-2})\)[/tex].
4. Interpreting the Result:
By performing the logarithm operation, you get approximately [tex]\(1.6989700043360187\)[/tex].
Therefore, the pOH of the solution is approximately [tex]\(1.70\)[/tex]. So the correct option from the given choices is B. [tex]\(1.70\)[/tex].
[tex]\[ \text{pOH} = -\log_{10}[\text{OH}^-] \][/tex]
Here are the steps to solve this:
1. Identify the Hydroxide Ion Concentration:
The concentration of hydroxide ions in the solution is [tex]\(2.0 \times 10^{-2}\)[/tex].
2. Calculate the pOH:
Use the formula [tex]\(\text{pOH} = -\log_{10}[2.0 \times 10^{-2}]\)[/tex].
3. Use a Calculator or Logarithm Table:
Evaluate [tex]\(-\log_{10}(2.0 \times 10^{-2})\)[/tex].
4. Interpreting the Result:
By performing the logarithm operation, you get approximately [tex]\(1.6989700043360187\)[/tex].
Therefore, the pOH of the solution is approximately [tex]\(1.70\)[/tex]. So the correct option from the given choices is B. [tex]\(1.70\)[/tex].
Thank you for reading the article What is the pOH of a solution with tex left OH right 2 0 times 10 2 tex A 3 01 B 1 70 C. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
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