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A 2.84 cc chamber is made up of a liter solution. If 50 cc of the solution neutralizes 38.2 cc, and I need to find the percentage of sulfuric acid in the chamber given that the specific gravity is 1.71, how do I proceed?

Answer :

The percentage of sulfuric acid in the chamber is 50.5%

Step 1: Calculate the number of moles of sodium hydroxide (NaOH) used to neutralize the sulfuric acid.

First, calculate the number of moles of NaOH:

Molarity of NaOH = 1 M (given)

Volume of NaOH = 50 cc = 0.05 L (converted to liters)

Moles of NaOH = Molarity * Volume (in liters) = 1 M * 0.05 L = 0.05 mol

Step 2: Calculate the number of moles of sulfuric acid (Hâ‚‚SOâ‚„) neutralized.

The reaction equation is: Hâ‚‚SOâ‚„ + 2NaOH → Naâ‚‚SOâ‚„ + 2Hâ‚‚O

From the equation, 1 mole of Hâ‚‚SOâ‚„ reacts with 2 moles of NaOH.

Moles of Hâ‚‚SOâ‚„ = Moles of NaOH / 2 = 0.05 mol / 2 = 0.025 mol

Step 3: Calculate the mass of sulfuric acid.

Molar mass of Hâ‚‚SOâ‚„ = 98.08 g/mol

Mass of Hâ‚‚SOâ‚„ = Moles * Molar mass = 0.025 mol * 98.08 g/mol = 2.452 g

Step 4: Calculate the volume of sulfuric acid solution.

Given: 2.84 cc of chamber solution contains 2.452 g of Hâ‚‚SOâ‚„.

Specific gravity of Hâ‚‚SOâ‚„ solution = 1.71

Step 5: Calculate the percentage of sulfuric acid.

Mass percentage = (Mass of Hâ‚‚SOâ‚„ / Mass of solution) * 100

To find the mass of the solution, use the specific gravity:

Mass of solution = Volume * Specific gravity = 2.84 cc * 1.71 = 4.8544 g

Percentage = (2.452 g / 4.8544 g) * 100 ≈ 50.5%

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Rewritten by : Jeany

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