College

Thank you for visiting 1 Byte addressing i 8 Address of array i Loop slli x10 x22 3 add x10 x10 x25 ld x9 0 x10 bne x9 x24. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

1. // Byte addressing, i*8 // Address of array[i]

Loop:
- slli x10, x22, 3
- add x10, x10, x25
- ld x9, 0(x10)
- bne x9, x24, Exit
- addi x22, x22, 1
- beq x0, x0, Loop

Exit: ...

Answer :

Final answer:

The provided code is in assembly language, specifically RISC-V, used for communicating directly with a computer's hardware. It implements a loop with several operations: logical left shift, addition, data loading from memory, branching in case of inequality or equality of register values.

Explanation:

The provided code is written in assembly language, specifically the RISC-V architecture. This language is used to communicate directly with a computer's hardware. In the provided code, a loop is being implemented and some operations are being performed within that loop. The slli instruction performs a logical left shift, while the add instruction adds two registers and stores the result. The ld instruction loads data from memory into a register, bne branches to a label if two register values are not equal, addi adds an immediate value to a register and stores the result, and beq branches to a label if two register values are equal.

Learn more about RISC-V Assembly Language here:

https://brainly.com/question/34484683

#SPJ11

Thank you for reading the article 1 Byte addressing i 8 Address of array i Loop slli x10 x22 3 add x10 x10 x25 ld x9 0 x10 bne x9 x24. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany

Other Questions