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How many grams of [tex]$Fe _2 O _3$[/tex] are there in 0.500 mole of [tex]$Fe _2 O _3$[/tex]?

A. 79.8 g
B. 160. g
C. 35.9 g
D. 63.8 g
E. 51.9 g

Answer :

To find out how many grams of [tex]\( \text{Fe}_2\text{O}_3 \)[/tex] are in 0.500 mole of [tex]\( \text{Fe}_2\text{O}_3 \)[/tex], you can follow these steps:

1. Determine the Molar Mass of [tex]\( \text{Fe}_2\text{O}_3 \)[/tex]:
- [tex]\( \text{Fe}_2\text{O}_3 \)[/tex] consists of iron (Fe) and oxygen (O).
- The atomic mass of iron (Fe) is approximately 55.845 g/mol.
- The atomic mass of oxygen (O) is approximately 16.00 g/mol.
- In [tex]\( \text{Fe}_2\text{O}_3 \)[/tex], there are 2 iron atoms and 3 oxygen atoms.
- Calculate the molar mass:
[tex]\[
\text{Molar mass of } \text{Fe}_2\text{O}_3 = 2 \times 55.845 + 3 \times 16.00 = 159.69 \, \text{g/mol}
\][/tex]

2. Calculate the Mass of 0.500 Mole of [tex]\( \text{Fe}_2\text{O}_3 \)[/tex]:
- Given moles of [tex]\( \text{Fe}_2\text{O}_3 = 0.500 \, \text{mol}\)[/tex].
- Use the molar mass to convert moles to grams:
[tex]\[
\text{Mass of } \text{Fe}_2\text{O}_3 = 0.500 \, \text{mol} \times 159.69 \, \text{g/mol} = 79.845 \, \text{g}
\][/tex]

Therefore, in 0.500 mole of [tex]\( \text{Fe}_2\text{O}_3 \)[/tex], there are approximately 79.8 grams.

Based on the options provided, the closest match is 79.8 g.

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