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The atomic mass of potassium is 39.1. What is the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium?

A. [tex]\quad 39.1 \, \text{mg}[/tex]
B. [tex]\quad 39.1 \, \text{g}[/tex]
C. [tex]\quad 39.1 \, \text{kg}[/tex]
D. [tex]\quad 6.02 \times 39.1 \, \text{mg}[/tex]
E. [tex]\quad 6.02 \times 39.1 \, \text{g}[/tex]

Answer :

Certainly! Let's break down the problem step-by-step.

1. Understand the Question:
- We need to find the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium.

2. Key Information:
- The atomic mass of potassium is given as 39.1.
- [tex]$6.02 \times 10^{23}$[/tex] is Avogadro’s number, which represents one mole of any substance.

3. Relate Atomic Mass and Moles:
- The atomic mass of an element, expressed in grams per mole (g/mol), indicates the mass of one mole of the atoms of that element.
- Therefore, the atomic mass of potassium, 39.1 g/mol, means that one mole (or [tex]$6.02 \times 10^{23}$[/tex] atoms) of potassium has a mass of 39.1 grams.

4. Conclusion:
- Since [tex]$6.02 \times 10^{23}$[/tex] atoms make up one mole, and the atomic mass tells us the mass of one mole, the mass of this quantity of potassium is 39.1 grams.

Thus, the correct answer is:
B. [tex]\( 39.1 \text{ g} \)[/tex]

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