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Answer :
The percentage is approximately 72.57%. To find the percentage of participants who correctly read at least 65 words in the average readers and poor spellers group, follow the same steps. The percentage is approximately 10.56%.
In order to find the percentage of participants who correctly read at least 92 words in the good readers and good spellers group, we first need to find the z-score for 92 words.
- Using the formula z = (x - μ) / σ, where x is the value we want to find the percentage for, μ is the mean, and σ is the standard deviation, we can calculate that the z-score is 0.6.
- We can then use a standard normal distribution table to find the percentage of participants who scored at least 0.6 standard deviations above the mean.
- The table gives us a value of 0.7257, which represents the area under the curve from 0 to 0.6.
- Therefore, the percentage of participants who correctly read at least 92 words in the good readers and good spellers group is approximately 72.57%.
To find the percentage of participants who correctly read at least 65 words in the average readers and poor spellers group, we follow the same steps.
- The z-score for 65 words is -1.25.
- Looking at the standard normal distribution table, the area under the curve from 0 to -1.25 is approximately 0.1056.
- Therefore, the percentage of participants who correctly read at least 65 words in the average readers and poor spellers group is approximately 10.56%.
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