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Answer :
Final answer:
In 1.70 moles of Mg3N2, there are 3.4 moles of Nitrogen.
Explanation:
In the given compound Mg3N2, one molecule contains two moles of nitrogen (N). Therefore, if you have 1.70 moles of Mg3N2, the number of moles of Nitrogen (N) in this will be 1.70 (moles of Mg3N2) x 2 (moles of N per mole of Mg3N2). Thus, you have 3.4 moles of Nitrogen in 1.70 moles of Mg3N2.
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