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A boy has 11 coins in dimes and quarters. Their value is [tex]$\$ 1.70$[/tex]. How many of each does he have?

Which of the following equations could be used to solve the problem?

A. [tex]0.10d + 0.25(11-d) = 1.70[/tex]
B. [tex]25d + 10(11-d) = 1.70[/tex]
C. [tex]d + (11-d) = 1.70[/tex]

Answer :

Sure! Let's solve this problem step by step.

We need to find out how many dimes and quarters the boy has, given that:

1. He has a total of 11 coins.
2. The total value of these coins is [tex]$1.70.

We can define:

- \( d \): the number of dimes.
- \( q \): the number of quarters.

From the information given, we can set up two equations:

1. The total number of coins equation:
\( d + q = 11 \)

2. The total value equation in dollars (remember, a dime is worth $[/tex]0.10 and a quarter is worth $0.25):
[tex]\( 0.10d + 0.25q = 1.70 \)[/tex]

Now, let's use these equations to solve for [tex]\( d \)[/tex] and [tex]\( q \)[/tex].

Step 1: Solve the first equation for one variable, say [tex]\( q \)[/tex].

[tex]\[
q = 11 - d
\][/tex]

Step 2: Substitute [tex]\( q = 11 - d \)[/tex] into the total value equation.

[tex]\[
0.10d + 0.25(11 - d) = 1.70
\][/tex]

Step 3: Simplify and solve for [tex]\( d \)[/tex].

[tex]\[
0.10d + 2.75 - 0.25d = 1.70
\][/tex]

Combine like terms:

[tex]\[
-0.15d + 2.75 = 1.70
\][/tex]

Subtract 2.75 from both sides:

[tex]\[
-0.15d = 1.70 - 2.75
\][/tex]

[tex]\[
-0.15d = -1.05
\][/tex]

Divide both sides by [tex]\(-0.15\)[/tex]:

[tex]\[
d = \frac{-1.05}{-0.15} = 7
\][/tex]

Step 4: Use the value of [tex]\( d \)[/tex] to find [tex]\( q \)[/tex].

[tex]\[
q = 11 - d = 11 - 7 = 4
\][/tex]

Thus, the boy has 7 dimes and 4 quarters.

The correct equation that can be used to solve this problem is:
[tex]\[ 0.10d + 0.25(11 - d) = 1.70 \][/tex]

This corresponds to the first equation option provided.

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Rewritten by : Jeany