Thank you for visiting A current of 5 A passes through a 2 ohm resistor for 30 minutes Calculate the electrical energy transferred A 900 J B 1800 J. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
A current of 5 A through a 2-ohm resistor for 30 minutes transfers 90,000 J of electrical energy, corresponding to option e. 9000 J.
Explanation:
To calculate the electrical energy transferred through a resistor, you can use the formula E = I2Rt, where E is the energy in joules (J), I is the current in amperes (A), R is the resistance in ohms (Ω), and t is the time in seconds (s).
In this case, a current (I) of 5 A passes through a 2-ohm resistor for 30 minutes. To find the energy, you first need to convert 30 minutes to seconds, which gives us 30 minutes × 60 seconds/minute = 1800 seconds. Then use the formula:
E = I2Rt
E = (5 A)2 × 2 Ω × 1800 s
E = 25 A2 × 2 Ω × 1800 s
E = 50 A2 Ω × 1800 s
E = 90,000 J
Therefore, the electrical energy transferred is 90,000 J, which corresponds to option e. 9000 J.
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