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In Rectangles ABCD, diagonals AC and DB bisect each other and the angles they intersect. Hence, Angle AEB in the given rectangle is 90 degrees.
In the rectangle ABCD, diagonals AC and DB intersect at point E.
Because ABCD is a rectangle, its diagonals are equal in length and bisect each other, diagonals of rectangle are perpendicular.
Therefore, they will 90 degrees.
Since Triangle AEB is isosceles (AE = BE), it follows from the property that the base angles of an isosceles triangle are equal.
Hence, Angle AEB will also be 90 degrees.
Learn more about Rectangles here:
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The probable question may be:
ABCD is a rectangle
Diagonal Ac and Diagonal DB intersect each other at E.
Angle DAE is 65 degree
find the measure of angle AEB.
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