Thank you for visiting Select the correct answer The atomic mass of potassium is 39 1 What is the mass of tex 6 02 times 10 23 tex atoms. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
To determine the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, we need to use the concept of moles and atomic mass:
1. Understanding Moles and Atomic Mass:
- The atomic mass of potassium is given as 39.1 grams per mole. This means one mole of potassium, which contains Avogadro's number of atoms ([tex]\(6.02 \times 10^{23}\)[/tex] atoms), has a mass of 39.1 grams.
2. Identify Avogadro's Number:
- Avogadro's number is [tex]\(6.02 \times 10^{23}\)[/tex] atoms per mole. This is a constant that expresses the number of atoms contained in one mole of any substance.
3. Calculate the Mass:
- Since [tex]\(6.02 \times 10^{23}\)[/tex] atoms corresponds to one mole of potassium, and the molar mass of potassium is 39.1 grams per mole, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is exactly the same as the atomic mass expressed in grams.
Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is [tex]\(\boxed{39.1 \, \text{g}}\)[/tex].
So, the correct answer is B. [tex]\(39.1 \, \text{g}\)[/tex].
1. Understanding Moles and Atomic Mass:
- The atomic mass of potassium is given as 39.1 grams per mole. This means one mole of potassium, which contains Avogadro's number of atoms ([tex]\(6.02 \times 10^{23}\)[/tex] atoms), has a mass of 39.1 grams.
2. Identify Avogadro's Number:
- Avogadro's number is [tex]\(6.02 \times 10^{23}\)[/tex] atoms per mole. This is a constant that expresses the number of atoms contained in one mole of any substance.
3. Calculate the Mass:
- Since [tex]\(6.02 \times 10^{23}\)[/tex] atoms corresponds to one mole of potassium, and the molar mass of potassium is 39.1 grams per mole, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is exactly the same as the atomic mass expressed in grams.
Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is [tex]\(\boxed{39.1 \, \text{g}}\)[/tex].
So, the correct answer is B. [tex]\(39.1 \, \text{g}\)[/tex].
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