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Answer :
Answer:
the time of fall of the stone is 15 s.
Step-by-step explanation:
Given;
height through which the stone was dropped, h = 3,600 ft
the initial velocity of the stone, u = 0
The time of fall of the stone is calculated using the following kinematic equation;
h = ut + ¹/â‚‚gt²
h = 0 + ¹/â‚‚gt²
h = ¹/â‚‚gt²
where;
g is acceleration due to gravity = 32.17 ft/s²
[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 3,600 \ ft}{32.17 \ ft/s^2} }\\\\t =14.96 \ s = 15 \ s[/tex]
Therefore, the time of fall of the stone is 15 s.
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