Thank you for visiting The amount of energy needed to heat 6 1 g of a substance from 50 0 C to 80 0 C is 36 6 J. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
As a result, the material has a specific heat capacity of 0.20 J/g°C.
How do you define simple specific heat capacity?
Its specific heat capacity is the amount of heat energy required to raise the temperature of a unit mass of any substance or matter by one degree Celsius.
We can use the following formula to find the substance's specific heat capacity: Q = m * c * ΔT
where Q is the extra energy in joules, m is the substance's mass in grammes, c is its specific heat capacity in joules per gramme of temperature, and T is the temperature change in degrees Celsius.
When we substitute the specified values, we obtain:
36.6 J = (6.1 g) * c * (80.0°C - 50.0°C)
Simplifying and solving for c, we get:
c = 36.6 J / (6.1 g * 30.0°C)
c = 0.20 J/g°C
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