Thank you for visiting How many formula units make up 39 4 g of magnesium chloride MgCl 2 Express the number of formula units numerically. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Approximately 2.48 × 10²³ formula units make up 39.4 g of magnesium chloride (MgCl2).
To determine the number of formula units in 39.4 g of magnesium chloride (MgCl2), we need to use the molar mass of magnesium chloride and Avogadro's number.
1. Find the molar mass of MgCl2:
- The atomic mass of magnesium (Mg) is approximately 24.31 g/mol.
- The atomic mass of chlorine (Cl) is approximately 35.45 g/mol.
- Since there are two chlorine atoms in one formula unit of MgCl2, we multiply the atomic mass of chlorine by 2.
The molar mass of MgCl2 is:
(1 × 24.31 g/mol) + (2 × 35.45 g/mol) = 95.21 g/mol
2. Use the molar mass and the given mass (39.4 g) to find the number of moles of MgCl2:
- Divide the given mass by the molar mass.
39.4 g / 95.21 g/mol ≈ 0.413 mol
3. Convert the number of moles to the number of formula units using Avogadro's number:
- Avogadro's number is approximately 6.022 × 10²³ formula units/mol.
Multiply the number of moles by Avogadro's number:
0.413 mol × 6.022 × 10²³ formula units/mol ≈ 2.48 × 10²³ formula units
Therefore, approximately 2.48 × 10²³ formula units make up 39.4 g of magnesium chloride (MgCl2).
To know more about Avogadro's number visit:
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