Thank you for visiting an object that is 2 84 tall is located 25 2 in front of a lens a virtual image is formed at a distance 36. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
To find the focal length of the lens, we can use the lens formula:
1/f = 1/v - 1/u
Where:
f is the focal length of the lens,
v is the distance of the virtual image from the lens, and
u is the distance of the object from the lens.
In this case, the object is located 25.2 inches in front of the lens, so u = -25.2 inches (negative because it is in front of the lens). The virtual image is formed at a distance of 36.6 inches from the lens, so v = 36.6 inches.
Substituting these values into the lens formula, we have:
1/f = 1/36.6 - 1/(-25.2)
Simplifying this equation, we get:
1/f = (1/36.6) + (1/25.2)
To combine the fractions, we need to find a common denominator. In this case, the least common multiple of 36.6 and 25.2 is 918, so we rewrite the equation as:
1/f = (25.2 + 36.6) / (36.6 * 25.2)
1/f = 61.8 / 918
1/f ≈ 0.0673
Now, we can take the reciprocal of both sides to find f:
f ≈ 1 / 0.0673
f ≈ 14.84 inches
Therefore, the focal length of the lens is approximately 14.84 inches.
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