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A local cafΓ© serves tea, coffee, cookies, scones, and muffins. They recently gathered data about their customers who purchase both a drink and a snack. The given frequency table shows the results of the survey.

If approximately [tex]$24\%$[/tex] of the customers surveyed have a scone with their tea and approximately [tex]$36\%$[/tex] of the customers surveyed buy a muffin, complete the column and row headings for the given table.

| | Muffin | Scone | Cookie | Total |
|----------|--------|-------|--------|-------|
| Coffee | 40 | 100 | 110 | 250 |
| Tea | 120 | 80 | 50 | 250 |
| Total | 160 | 180 | 160 | 500 |

Answer :

We begin by noting that the survey was of 500 customers, each purchasing one drink and one snack. The cafΓ© offers two drinks (tea and coffee) and three snacks (cookies, muffins, and scones). The incomplete frequency table is as follows:

[tex]$$
\begin{array}{|c|c|c|c|c|}
\hline
& \,\,\,\,?\,\,\, & \,\,\,\,?\,\,\, & \,\,\,\,?\,\,\, & \text{Total} \\
\hline
\text{Row 1: } & 40 & 100 & 110 & 250 \\
\hline
\text{Row 2: } & 120 & 80 & 50 & 250 \\
\hline
\text{Total} & 160 & 180 & 160 & 500 \\
\hline
\end{array}
$$[/tex]

We are given two pieces of information:

1. Approximately [tex]$36\%$[/tex] of the customers (of 500) buy a muffin.
2. Approximately [tex]$24\%$[/tex] of the tea drinkers have a scone with their tea.

Let’s use these facts step by step.

–––––––––––––––––––––––––––––––––––––––
Step 1. Identify the Muffin Column

The total number of customers who buy a muffin is
[tex]$$0.36 \times 500 = 180.$$[/tex]
Looking at the column totals, the column that sums to 180 must correspond to muffins. Hence, the column with total 180 is for muffins.

–––––––––––––––––––––––––––––––––––––––
Step 2. Assign Drinks (Rows)

The only two drinks are tea and coffee. The table shows two rows with equal totals of 250 customers each. One row corresponds to tea drinkers and the other to coffee drinkers. We will decide which row is tea by using the second piece of information.

–––––––––––––––––––––––––––––––––––––––
Step 3. Match the Tea-Scone Information

We are told that approximately [tex]$24\%$[/tex] of the tea customers have a scone. Since there are 250 tea customers, we would ideally have
[tex]$$0.24 \times 250 = 60$$[/tex]
tea customers ordering scones. Inspect the two rows in the column β€œscones” (the column that is not yet assigned). The two values available in the unassigned scone column are [tex]$110$[/tex] and [tex]$50$[/tex]. No cell exactly gives 60, but the count [tex]$50$[/tex] is closer to the desired value (and within the range of approximation given the circumstances).

Thus, we assign the row containing [tex]$50$[/tex] in the scone column as the tea row. Consequently, the other row (with [tex]$110$[/tex] in the scone column) is the coffee row.

–––––––––––––––––––––––––––––––––––––––
Step 4. Assign the Remaining Snack Columns

We already have:
- The column with total [tex]$180$[/tex] is muffins.

Now, the remaining two snack columns (with totals [tex]$160$[/tex] each) must be assigned among cookies and scones. Since we already determined from Step 3 that in the tea row the scone count is [tex]$50$[/tex], we choose the column that provides this [tex]$50$[/tex] for tea as the scone column. That leaves the other column (with total [tex]$160$[/tex]) to be cookies.

–––––––––––––––––––––––––––––––––––––––
Step 5. Write the Final Table with Headings

The final assigned headings are:

- Drinks (rows):
- Row 1: Coffee
- Row 2: Tea

- Snacks (columns):
- Column 1: Cookies (total = 160)
- Column 2: Muffins (total = 180)
- Column 3: Scones (total = 160)

Thus, the completed table is:

[tex]$$
\begin{array}{|l|c|c|c|c|}
\hline
& \textbf{Cookies} & \textbf{Muffins} & \textbf{Scones} & \textbf{Total} \\
\hline
\textbf{Coffee} & 40 & 100 & 110 & 250 \\
\hline
\textbf{Tea} & 120 & 80 & 50 & 250 \\
\hline
\textbf{Total} & 160 & 180 & 160 & 500 \\
\hline
\end{array}
$$[/tex]

–––––––––––––––––––––––––––––––––––––––
Step 6. Check the Conditions

1. Muffins: The muffin column total is [tex]$180$[/tex], which is exactly [tex]$36\%$[/tex] of 500 since [tex]$$\frac{180}{500} \times 100 = 36\%.$$[/tex]
2. Tea with scones: In the tea row, the scone count is [tex]$50$[/tex]. This is approximately [tex]$$\frac{50}{250} \times 100 = 20\%.$$[/tex]
Although [tex]$20\%$[/tex] is not exactly [tex]$24\%$[/tex], [tex]$50$[/tex] is the closest available value from the survey that can be assigned.

–––––––––––––––––––––––––––––––––––––––
Conclusion

Based on the information provided:

- The row headings are: Row 1 = Coffee and Row 2 = Tea.
- The column headings for the snacks are: Column 1 = Cookies, Column 2 = Muffins, Column 3 = Scones.

The final table is:

[tex]$$
\begin{array}{|l|c|c|c|c|}
\hline
& \textbf{Cookies} & \textbf{Muffins} & \textbf{Scones} & \textbf{Total} \\
\hline
\textbf{Coffee} & 40 & 100 & 110 & 250 \\
\hline
\textbf{Tea} & 120 & 80 & 50 & 250 \\
\hline
\textbf{Total} & 160 & 180 & 160 & 500 \\
\hline
\end{array}
$$[/tex]

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Rewritten by : Jeany